At a certain location, the solar power per unit area reaching the Earth’s surface is 215 W/m2, averaged over a 24 hour day. If you live in a house whose average power requirement is 3 kW and you can convert solar power to electric power with 14 percent efficiency, how large a collector area will you need to meet all your household energy requirements from solar energy?

Best answer:

Answer by Denis S
e*A*(215)=3000
A=3000/((215)(0.14))
A=99.7 m^2

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